Linear Combination of Non-Parallel Complex Numbers is Zero if Factors are Both Zero

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Theorem

Let $z_1$ and $z_2$ be complex numbers expressed as vectors such taht $z_1$ is not parallel to $z_2$.

Let $a, b \in \R$ be real numbers such that:

$a z_1 + b z_2 = 0$

Then $a = 0$ and $b = 0$.


Proof

Suppose it is not the case that $a = b = 0$.

Then:

\(\ds a z_1 + b z_2\) \(=\) \(\ds 0\)
\(\ds \leadstoandfrom \ \ \) \(\ds a \paren {x_1 + i y_1} + b \paren {x_2 + i y_2}\) \(=\) \(\ds 0\)
\(\ds \leadstoandfrom \ \ \) \(\ds a x_1 + b x_2\) \(=\) \(\ds 0\)
\(\ds a y_1 + b y_2\) \(=\) \(\ds 0\)
\(\ds \leadstoandfrom \ \ \) \(\ds a x_1\) \(=\) \(\ds -b x_2\)
\(\ds a y_1\) \(=\) \(\ds -b y_2\)
\(\ds \leadstoandfrom \ \ \) \(\ds \dfrac {y_1} {x_1}\) \(=\) \(\ds \dfrac {y_2} {x_2}\)

and $z_1$ and $z_2$ are parallel.

$\blacksquare$


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