Linear Isometry is Injective
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Theorem
Let $\struct {X, \norm \cdot_X}$ and $\struct {Y, \norm \cdot_Y}$ be normed vector spaces.
Let $T : X \to Y$ be a linear isometry.
Then $T$ is injective.
Corollary
$T$ is an isometric isomorphism if and only if it is surjective.
Proof
Let $x, y \in X$.
We have:
- $\norm {\map T {x - y} }_Y = \norm {T x - T y}_Y$
from the definition of a linear transformation.
Since $T$ is a linear isometry, we have:
- $\norm {\map T {x - y} }_Y = \norm {x - y}_X$
So:
- $\norm {T x - T y}_Y = 0$
- $\norm {x - y}_X = 0$
Since the norm is positive definite, this gives:
- $T x = T y$
- $x = y$
So $T$ is injective.
$\blacksquare$