Magic Constant of Smallest Prime Magic Square with Consecutive Primes

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Theorem

The magic constant of the smallest prime magic square whose elements are consecutive odd primes is $4 \, 440 \, 084 \, 513$.


Proof

The smallest prime magic square whose elements are consecutive odd primes is:

$\begin{array}{|c|c|c|}

\hline 1 \, 480 \, 028 \, 159 & 1 \, 480 \, 028 \, 153 & 1 \, 480 \, 028 \, 201 \\ \hline 1 \, 480 \, 028 \, 213 & 1 \, 480 \, 028 \, 171 & 1 \, 480 \, 028 \, 129 \\ \hline 1 \, 480 \, 028 \, 141 & 1 \, 480 \, 028 \, 189 & 1 \, 480 \, 028 \, 183 \\ \hline \end{array}$


As can be seen by inspection, the sums of the elements in the rows, columns and Diagonal of Array is $4 \, 440 \, 084 \, 513$:

\(\ds 1 \, 480 \, 028 \, 159 + 1 \, 480 \, 028 \, 153 + 1 \, 480 \, 028 \, 201\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)
\(\ds 1 \, 480 \, 028 \, 213 + 1 \, 480 \, 028 \, 171 + 1 \, 480 \, 028 \, 129\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)
\(\ds 1 \, 480 \, 028 \, 141 + 1 \, 480 \, 028 \, 189 + 1 \, 480 \, 028 \, 183\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)


\(\ds 1 \, 480 \, 028 \, 159 + 1 \, 480 \, 028 \, 213 + 1 \, 480 \, 028 \, 141\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)
\(\ds 1 \, 480 \, 028 \, 153 + 1 \, 480 \, 028 \, 171 + 1 \, 480 \, 028 \, 189\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)
\(\ds 1 \, 480 \, 028 \, 201 + 1 \, 480 \, 028 \, 129 + 1 \, 480 \, 028 \, 183\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)


\(\ds 1 \, 480 \, 028 \, 159 + 1 \, 480 \, 028 \, 171 + 1 \, 480 \, 028 \, 183\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)
\(\ds 1 \, 480 \, 028 \, 141 + 1 \, 480 \, 028 \, 171 + 1 \, 480 \, 028 \, 201\) \(=\) \(\ds 4 \, 440 \, 084 \, 513\)