Open Ball Centred at Origin in Normed Vector Space is Symmetric
Jump to navigation
Jump to search
Theorem
Let $\struct {X, \norm \cdot}$ be a normed vector space.
Let $\map B {0, r}$ be the open ball in $X$ centered at $0$ with radius $r$.
Then $\map B {0, r}$ is symmetric.
Proof
Let $x \in \map B {0, r}$.
Then:
- $\norm x < r$
We then have:
- $\norm {-x} = \cmod {-1} \norm x = \norm x < r$
So $-x \in \map B {0, r}$.
So $\map B {0, r}$ is symmetric.
$\blacksquare$