Point Spectrum of Densely-Defined Linear Operator consists of its Eigenvalues
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Theorem
Let $\struct {\HH, \innerprod \cdot \cdot}$ be a Hilbert space over $\C$.
Let $\struct {\map D T, T}$ be a densely-defined linear operator.
Let $\map {\sigma_p} T$ be the point spectrum of $T$.
Then $\lambda \in \map {\sigma_p} T$ if and only if $\lambda$ is an eigenvalue of $T$.
Proof
We have that $\lambda \in \map {\sigma_p} T$ if and only if:
- $T - \lambda I$ is not injective.
That is, if and only if there exists $x \in \map D T \setminus \set 0$ such that:
- $\paren {T - \lambda I} x = \map {\paren {T - \lambda I} } 0 = 0$
So $\lambda \in \map {\sigma_p} T$ if and only if there exists $x \in \map D T \setminus \set 0$ such that:
- $T x = \lambda I x = \lambda x$
That is, $\lambda \in \map {\sigma_p} T$ if and only if $\lambda$ is an eigenvalue of $T$.
$\blacksquare$