Product of Element in *-Star Algebra with its Star is Hermitian
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Theorem
Let $\struct {A, \ast}$ be a $\ast$-algebra.
Let $a \in A$.
Then $a^\ast a$ and $a a^\ast$ are Hermitian.
Proof
We have:
\(\ds \paren {a^\ast a}^\ast\) | \(=\) | \(\ds a^\ast \paren {a^\ast}^\ast\) | $(\text C^\ast 3)$ | |||||||||||
\(\ds \) | \(=\) | \(\ds a^\ast a\) | $(\text C^\ast 1)$ |
and:
\(\ds \paren {a a^\ast}^\ast\) | \(=\) | \(\ds \paren {a^\ast}^\ast a^\ast\) | $(\text C^\ast 3)$ | |||||||||||
\(\ds \) | \(=\) | \(\ds a a^\ast\) | $(\text C^\ast 1)$ |
So $a^\ast a$ and $a a^\ast$ are both Hermitian.
$\blacksquare$
Sources
- 1990: Gerard J. Murphy: C*-Algebras and Operator Theory ... (previous) ... (next): $2.1$: $C^\ast$-Algebras