Riesz-Markov-Kakutani Representation Theorem/Lemma 5
Lemma for Riesz-Markov-Kakutani Representation Theorem
Let $\struct {X, \tau}$ be a locally compact Hausdorff space.
Let $\map {C_c} X$ be the space of continuous complex functions with compact support on $X$.
Let $\Lambda$ be a positive linear functional on $\map {C_c} X$.
There exists a $\sigma$-algebra $\MM$ over $X$ which contains the Borel $\sigma$-algebra of $\struct {X, \tau}$.
There exists a unique complete Radon measure $\mu$ on $\MM$ such that:
- $\ds \forall f \in \map {C_c} X: \Lambda f = \int_X f \rd \mu$
Notation
For an open set $V \in \tau$ and a mapping $f \in \map {C_c} X$:
- $f \prec V \iff \supp f \subset V$
where $\supp f$ denotes the support of $f$.
The validity of the material on this page is questionable. In particular: The proof does not work with this definition. Something should be forgotten. Maybe, $f \prec V \iff 0 \le f \le {\mathbf 1}_V$? You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by resolving the issues. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Questionable}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
For a compact set $K \subset X$ and a mapping $f \in \map {C_c} X$:
- $K \prec f \iff \forall x \in K: \map f x = 1$
Construction of $\mu$ and $\MM$
For every $V \in \tau$, define:
- $\map {\mu_1} V = \sup \set {\Lambda f: f \prec V}$
The validity of the material on this page is questionable. In particular: The definition of $\mu_1$ seems wrong, as $\map {\mu_1} V \in \set {0, +\infty}$ for all $V$. Indeed, for each $c>0$, $f \prec V \iff c f \prec V $. This means $\map {\mu_1} V = c \map {\mu_1} V$ for all $c > 0$. You can help $\mathsf{Pr} \infty \mathsf{fWiki}$ by resolving the issues. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Questionable}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Note that $\mu_1$ is monotonically increasing.
That is, for all $V, W \in \tau$ such that $V \subset W$, we have:
\(\ds \map {\mu_1} V\) | \(=\) | \(\ds \sup \set {\Lambda f: \supp f \subset V}\) | ||||||||||||
\(\ds \) | \(\le\) | \(\ds \sup \set {\Lambda f: \supp f \subset W}\) | \(\ds = \map {\mu_1} W\) |
$\Box$
For every other subset $E \subset X$, define:
- $\map \mu E = \inf \set {\map {\mu_1} V: V \supset E \land V \in \tau}$
Since $\mu_1$ is monotonically increasing:
- $\mu_1 = \mu {\restriction_\tau}$
Define:
- $\MM_F = \set {E \subset X : \map \mu E < \infty \land \map \mu E = \sup \set {\map \mu K: K \subset E \land K \text { compact} } }$
Define:
- $\MM = \set {E \subset X : \forall K \subset X \text { compact}: E \cap K \in \MM_F}$
Lemma
$\set {V \in \tau: \map \mu V < \infty} \subset \MM_F$
Proof
Since $\mu$ and $\mu_1$ coincide on $\tau$, by definition of $\mu_1$, for all $\alpha < \map \mu V$, there exists some $f \in \map {C_c} X: f \prec V$ such that $\Lambda f > \alpha$.
Let $K = \supp f$.
For all $W \in \tau$ such that $K \subset W$:
- $f \prec W$
So, by definition of $\mu_1$:
- $\Lambda f \le \map \mu W$
By definition of $\mu$:
- $\Lambda f \le \map \mu K$
So:
- $\alpha < \map \mu K$
That is, for all $\alpha < \map \mu V$, there exists some compact $K \subset V$ such that:
- $\alpha < \map \mu K \le \map \mu V$
Since $V$ was arbitrary:
- $\set {V \in \tau: \map \mu V < \infty} \subset \MM_F$
$\blacksquare$