Roots of Complex Number/Examples/Square Roots of 4 root 2 + 4 root 2 i
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Example of Roots of Complex Number
The complex square roots of $4 \sqrt 2 + 4 \sqrt 2 i$ are given by:
- $\paren {4 \sqrt 2 + 4 \sqrt 2 i}^{1/2} = \set {\sqrt 8 \cis 22.5 \degrees, \sqrt 8 \cis 202.5 \degrees}$
Proof
Let $z^2 = 4 \sqrt 2 + 4 \sqrt 2 i$.
We have that:
- $z^2 = 8 \paren {\dfrac {\sqrt 2} 2 + \dfrac {\sqrt 2} 2 i}$
and it is seen that:
- $\dfrac {\sqrt 2} 2 + \dfrac {\sqrt 2} 2 i = \cis \dfrac \pi 4$
Hence
\(\ds z^2\) | \(=\) | \(\ds 8 \cis \dfrac \pi 4\) | ||||||||||||
\(\ds \leadsto \ \ \) | \(\ds z\) | \(=\) | \(\ds \sqrt 8 \, \paren {\cis \dfrac \pi 8 + k \pi}\) | where $k = 0, 1$ | ||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt 8 \cis \dfrac \pi 8 \text { and } \sqrt 8 \cis \dfrac {9 \pi} 8\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \sqrt 8 \cis 22.5 \degrees \text { and } \sqrt 8 \cis 202.5 \degrees\) |
$\blacksquare$
Sources
- 1981: Murray R. Spiegel: Theory and Problems of Complex Variables (SI ed.) ... (previous) ... (next): $1$: Complex Numbers: Supplementary Problems: Roots of Complex Numbers: $96 \ \text{(b)}$