# Rule of Transposition/Formulation 1/Proof 1

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## Theorem

- $p \implies q \dashv \vdash \neg q \implies \neg p$

## Proof

### Proof of Forward Implication

By the tableau method of natural deduction:

Line | Pool | Formula | Rule | Depends upon | Notes | |
---|---|---|---|---|---|---|

1 | 1 | $p \implies q$ | Premise | (None) | ||

2 | 2 | $\neg q$ | Assumption | (None) | ||

3 | 1, 2 | $\neg p$ | Modus Tollendo Tollens (MTT) | 1, 2 | ||

4 | 1 | $\neg q \implies \neg p$ | Rule of Implication: $\implies \II$ | 2 – 3 | Assumption 2 has been discharged |

$\blacksquare$

### Proof of Reverse Implication

By the tableau method of natural deduction:

Line | Pool | Formula | Rule | Depends upon | Notes | |
---|---|---|---|---|---|---|

1 | 1 | $\neg q \implies \neg p$ | Premise | (None) | ||

2 | 2 | $p$ | Assumption | (None) | ||

3 | 2 | $\neg \neg p$ | Double Negation Introduction: $\neg \neg \II$ | 2 | ||

4 | 1, 2 | $\neg \neg q$ | Modus Tollendo Tollens (MTT) | 1, 3 | ||

5 | 1, 2 | $q$ | Double Negation Elimination: $\neg \neg \EE$ | 4 | ||

6 | 1 | $p \implies q$ | Rule of Implication: $\implies \II$ | 2 – 5 | Assumption 2 has been discharged |

### Law of the Excluded Middle

The proof of the reverse implication depends on the Law of the Excluded Middle, by way of Double Negation Elimination.

This is one of the axioms of logic that was determined by Aristotle, and forms part of the backbone of classical (Aristotelian) logic.

However, the intuitionist school rejects the Law of the Excluded Middle as a valid logical axiom.

This in turn invalidates the proof of the reverse implication from an intuitionistic perspective.