Schröder Rule/Proof 1
Theorem
Let $A$, $B$ and $C$ be relations on a set $S$.
The following statements are equivalent:
- $(1): \quad A \circ B \subseteq C$
- $(2): \quad A^{-1} \circ \overline C \subseteq \overline B$
- $(3): \quad \overline C \circ B^{-1} \subseteq \overline A$
where:
- $\circ$ denotes relation composition
- $A^{-1}$ denotes the inverse of $A$
- $\overline A$ denotes the complement of $A$.
Proof
$(1)$ iff $(2)$
By the definition of relation composition and subset we have that statement $(1)$ may be written as:
- $(1'): \quad \forall x, y, z \in S: \paren {\tuple {y, z} \in A \land \tuple {x, y} \in B \implies \tuple {x, z} \in C}$
Using a different arrangement of variable names, statement $(2)$ can be written:
- $(2'): \quad \forall x, y, z \in S: \paren {\tuple {z, y} \in A^{-1} \land \tuple {x, z} \in \overline C \implies \tuple {x, y} \in \overline B}$
By the definition of inverse relation and the complement of a relation we can rewrite this as:
- $(2''): \quad \forall x, y, z \in S: \paren {\tuple {y, z} \in A \land \tuple {x, z} \notin C) \implies \tuple {x, y} \notin B}$
We shall use the method of truth tables.
The two statements will be equivalent if and only if the columns under the main connectives, which is $\implies$ in each case, are identical.
Statement 1:
$\begin{array}{ccccc} (\tuple {y, z} \in A & \land & \tuple {x, y} \in B) & \implies & \tuple {x, z} \in C \\ \hline \T & \T & \T & \T & \T \\ \T & \T & \T & \F & \F \\ \T & \F & \F & \T & \T \\ \T & \F & \F & \T & \F \\ \F & \F & \T & \T & \T \\ \F & \F & \T & \T & \F \\ \F & \F & \F & \T & \T \\ \F & \F & \F & \T & \F \\ \end{array}$
Statement 2:
$\begin{array}{ccccc} (\tuple {y, z} \in A & \land & \tuple {x, z} \notin C) & \implies & \tuple {x, y} \notin B \\ \hline \T & \F & \F & \T & \F \\ \T & \T & \T & \F & \F \\ \T & \F & \F & \T & \T \\ \T & \T & \T & \T & \T \\ \F & \F & \F & \T & \F \\ \F & \F & \T & \T & \F \\ \F & \F & \F & \T & \T \\ \F & \F & \T & \T & \T \\ \end{array}$
$\Box$
$(2)$ iff $(3)$
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Source of Name
This entry was named for Friedrich Wilhelm Karl Ernst Schröder.
Sources
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- 2010: Gunther Schmidt: Relational Mathematics: $\S 4$ Proposition $4.4$