Sets of Operations on Set of 3 Elements/Isomorphism Classes
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Theorem
Let $S = \set {a, b, c}$ be a set with $3$ elements.
Let $\MM$ be the set of all operations $\circ$ on $S$.
Then the elements of $\MM$ are divided in $3330$ isomorphism classes.
That is, up to isomorphism, there are $3330$ operations on $S$.
Proof
From Automorphism Group of $\AA$: Isomorphism Classes:
- each element of $\AA$ is in its own isomorphism class.
Hence $\AA$ contributes $3$ isomorphism classes.
From Automorphism Group of $\BB$: Isomorphism Classes:
- the $24$ elements of $\BB$ form $12$ isomorphism classes in pairs.
From Automorphism Group of $\CC_n$: Isomorphism Classes:
- the $3 \times 78$ elements of $\CC$ form $78$ isomorphism classes in threes.
From Automorphism Group of $\DD$: Isomorphism Classes:
- the $19 \, 422$ elements of $\DD$ form $3237$ isomorphism classes in sixes.
Thus there are $3 + 12 + 78 + 3237 = 3330$ isomorphism classes.
$\blacksquare$
Sources
- 1965: Seth Warner: Modern Algebra ... (previous) ... (next): Chapter $\text {II}$: New Structures from Old: $\S 8$: Compositions Induced on Subsets: Exercise $8.14 \ \text{(b)}$