Structure Induced by Lattice Operations is Lattice
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Theorem
Let $\struct {L, \vee, \wedge, \preceq}$ be a lattice.
Let $S$ be a set.
Let $\struct {L^S, \veebar, \barwedge}$ be the structure on $T^S$ induced by $\vee$ and $\wedge$.
Let $\precsim$ be the ordering on $S$ defined by:
- $\forall f, g \in L^S: f \precsim g$ if and only if $f \veebar g = g$
as on Semilattice Induces Ordering.
Then $\struct {L^S, \veebar, \barwedge, \precsim}$ is a lattice.
Proof
$\struct {L^S, \veebar}$ and $\struct {L^S, \barwedge}$ are Semilattices
By definition of lattice:
- $\struct {L, \vee}$ and $\struct {L, \wedge}$ are semilattices.
From Structure Induced by Semilattice Operation is Semilattice:
- $\struct {L^S, \veebar}$ and $\struct {L^S, \veebar}$ are semilattices.
$\Box$
Absorption Laws
By definition of lattice:
- $\vee$ absorbs $\wedge$
and:
- $\wedge$ absorbs $\vee$
From Structure Induced by Absorbing Operations is Absorbing
- $\veebar$ absorbs $\barwedge$
and:
- $\barwedge$ absorbs $\veebar$
$\Box$
It follows that $\struct {L^S, \veebar, \barwedge, \precsim}$ is a lattice by definition.
$\blacksquare$