Talk:Spectrum of Self-Adjoint Bounded Linear Operator is Real and Closed/Proof 2
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This seems insufficient. Basically you've shown that eigenvalues of $\R$ are real. I am not sure how to then get that $A - \lambda I$ is surjective. That it's injective and has bounded inverse (defined on the image of $A - \lambda I$) is obvious, but I am not sure how useful this inequality is to get surjectivity or denseness of the image. (which would imply surjectivity) Caliburn (talk) 21:38, 25 February 2023 (UTC)