Topological Dual Space of Hausdorff Locally Convex Space Separates Points
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Theorem
Let $\GF \in \set {\R, \C}$.
Let $\struct {X, \PP}$ be a Hausdorff locally convex space over $\GF$.
Let $X^\ast$ be the topological dual of $X$.
Let $x \in X$.
Then $X^\ast$ separates points.
That is, if $x, y \in X$ are such that:
- $\map f x = \map f y$ for all $f \in X^\ast$
we have that $x = y$.
Proof
Suppose $x \ne y$.
It suffices to find $f \in X^\ast$ such that $\map f x \ne \map f y$.
From Finite Topological Space is Compact, $\set {\mathbf 0_X}$ is compact.
From Compact Subspace of Hausdorff Space is Closed, $\set {\mathbf 0_X}$ is closed.
Since $x \ne y$, we have:
- $x - y \not \in X \setminus \set {\mathbf 0_X}$
From Existence of Non-Zero Continuous Linear Functional vanishing on Proper Closed Subspace of Hausdorff Locally Convex Space, there exists $f \in X^\ast$ such that:
- $\map f {x - y} \ne 0$
That is:
- $\map f x \ne \map f y$
$\blacksquare$