Vertical Section preserves Subsets
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Theorem
Let $X$ and $Y$ be sets.
Let $A \subseteq B$ be subsets of $X \times Y$.
Let $x \in X$.
Then:
- $A_x \subseteq B_x$
where $A_x$ is the $x$-vertical section of $A$ and $B_x$ is the $x$-vertical section of $B$.
Proof
Note that if:
- $y \in A_x$
from the definition of $x$-vertical section, we have:
- $\tuple {x, y} \in A$
so:
- $\tuple {x, y} \in B$
So, from the definition of $x$-vertical section, we have:
- $y \in B_x$
So:
- if $y \in A_x$ then $y \in B_x$.
That is:
- $A_x \subseteq B_x$
$\blacksquare$