Cofunction of Cofunction
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Theorem
Let $g$ be a cofunction of $f$.
Then $f$ is a cofunction of $g$.
That is, cofunctions exist in pairs.
Proof
That is:
\(\ds \forall x \in \R: \, \) | \(\ds \map g x\) | \(=\) | \(\ds \map f {90 \degrees - x}\) | Definition of Cofunction | ||||||||||
\(\ds \map g {90 \degrees - x}\) | \(=\) | \(\ds \map f {90 \degrees - \paren {90 \degrees - x} }\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \map f x\) |
Hence the result by definition of cofunction.
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): cofunctions
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): cofunctions