Convex Absorbing Set contained between Sets in terms of Minkowski Functional
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Theorem
Let $\GF \in \set {\R, \C}$.
Let $\struct {X, \tau}$ be a topological vector space over $\GF$.
Let $C$ be a convex absorbing set.
Let $\mu_C$ be the Minkowski functional of $C$.
Then we have:
- $\set {x \in X : \map {\mu_C} x < 1} \subseteq C \subseteq \set {x \in X : \map {\mu_C} x \le 1}$
Proof
Let $x \in X$ be such that $\map {\mu_C} x < 1$.
Then:
- $\inf \set {t > 0 : \dfrac x t \in C} < 1$
So there exists $t < 1$ such that $x \in t C$.
From Absorbing Set in Vector Space contains Zero Vector, we have that ${\mathbf 0}_X \in C$.
So, we have, since $C$ is convex:
- $x = x + \paren {1 - t} {\mathbf 0}_X \in t C + \paren {1 - t} C \subseteq C$
So $x \in C$.
So we have:
- $\set {x \in X : \map {\mu_C} x < 1} \subseteq C$
Now let $x \in C$.
We clearly have:
- $1 \in \set {t > 0 : \dfrac x t \in C}$
So:
- $\map {\mu_C} x = \inf \set {t > 0 : \dfrac x t \in C} \le 1$
Hence we obtain the inclusion:
- $C \subseteq \set {x \in X : \map {\mu_C} x \le 1}$
$\blacksquare$