Cotangent Additive Formula
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Theorem
Let $n \in \N_{>0}$ where $\N_{>0}$ denotes the non-zero natural numbers.
Let $z \in \C$ such that $\map \sin {n z} \ne 0$
Then:
- $\ds \map \cot {n z} = \frac 1 n \sum_{k \mathop = 0}^{n - 1} \map \cot {z + \frac {k \pi} n}$
where $\cot$ denotes the cotangent function.
Proof
\(\ds \map \sin {n z}\) | \(=\) | \(\ds 2^{n - 1} \prod_{k \mathop = 0}^{n - 1} \map \sin {z + \frac {k \pi} n}\) | Product Formula for Sine | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds \map \ln {\map \sin {n z} }\) | \(=\) | \(\ds \paren {n - 1} \ln 2 + \sum_{k \mathop = 0}^{n - 1} \map \ln {\map \sin {z + \frac {k \pi} n} }\) | taking the natural logarithm of both sides, Sum of Logarithms/Natural Logarithm | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds n \map \cot {n z}\) | \(=\) | \(\ds \sum_{k \mathop = 0}^{n - 1} \map \cot {z + \frac {k \pi} n}\) | taking the derivative of both sides, Derivative of Natural Logarithm Function, Derivative of Sine Function | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds \map \cot {n z}\) | \(=\) | \(\ds \frac 1 n \sum_{k \mathop = 0}^{n - 1} \map \cot {z + \frac {k \pi} n}\) | dividing by $n$ |
$\blacksquare$