Derivative Operator is Linear Mapping
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Theorem
Let $I := \closedint a b$ be a closed real interval.
Let $C \closedint a b$ be the space of real-valued functions continuous on $I$.
Let $C^1 \closedint a b$ be the space of real-valued functions continuously differentiable on $I$.
Let $D$ be the derivative operator such that:
- $D : \map {C^1} I \to \map C I$
and $Dx := x'$.
Then $D$ is a linear mapping.
Proof
Distributivity
\(\ds \map D {x + y}\) | \(=\) | \(\ds \paren {x + y}'\) | Definition | |||||||||||
\(\ds \) | \(=\) | \(\ds x' + y'\) | Sum Rule for Derivatives | |||||||||||
\(\ds \) | \(=\) | \(\ds Dx + Dy\) | Definition |
$\Box$
Positive homogenity
\(\ds \map D {\alpha x}\) | \(=\) | \(\ds \paren {\alpha x}'\) | Definition | |||||||||||
\(\ds \) | \(=\) | \(\ds \alpha x'\) | Derivative of Constant Multiple | |||||||||||
\(\ds \) | \(=\) | \(\ds \alpha Dx\) | Definition |
$\Box$
By definition, $D$ is a linear mapping
$\blacksquare$
Sources
- 2017: Amol Sasane: A Friendly Approach to Functional Analysis ... (previous) ... (next): Chapter $\S 2.1$: Continuous and linear maps. Linear transformations