Eliminant of Consistent Simultaneous Linear Equations is Zero

Theorem

Let $S$ be a system of simultaneous linear equations.

Let $S$ be consistent.

Then the eliminant of $S$ is zero.

Proof

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Sources

• 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): eliminant (resultant)
• 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): eliminant (resultant)