Henry Ernest Dudeney/Puzzles and Curious Problems/148 - A Menagerie/Solution

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Puzzles and Curious Problems by Henry Ernest Dudeney: $148$

A Menagerie
A travelling menagerie contained two freaks of nature -- a four-footed bird and a six-footed calf.
An attendant was asked how many birds and beasts there were in the show, and he said:
"Well, there are $36$ heads and $100$ feet altogether.
You can work it out for yourself."


Solution

There are $12$ beasts and $24$ birds.


Proof

Let $a$ and $b$ be the number of beasts and birds respectively.

If the anomalies had the usual number of legs, there would be $96$ feet altogether.

Hence we have:

\(\text {(1)}: \quad\) \(\ds a + b\) \(=\) \(\ds 36\) as they each have one head
\(\text {(2)}: \quad\) \(\ds 4 a + 2 b\) \(=\) \(\ds 96\) as (normal) beasts have $4$ legs and birds $2$
\(\text {(3)}: \quad\) \(\ds \leadsto \ \ \) \(\ds 2 a + 2 b\) \(=\) \(\ds 72\) $(1) \times 2$
\(\ds \leadsto \ \ \) \(\ds 2 a\) \(=\) \(\ds 24\) $(2) - (3)$
\(\ds \leadsto \ \ \) \(\ds a\) \(=\) \(\ds 12\)
\(\ds \leadsto \ \ \) \(\ds b\) \(=\) \(\ds 24\)

$\blacksquare$


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