Henry Ernest Dudeney/Puzzles and Curious Problems/148 - A Menagerie/Solution
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Puzzles and Curious Problems by Henry Ernest Dudeney: $148$
- A Menagerie
- A travelling menagerie contained two freaks of nature -- a four-footed bird and a six-footed calf.
- An attendant was asked how many birds and beasts there were in the show, and he said:
- "Well, there are $36$ heads and $100$ feet altogether.
- You can work it out for yourself."
Solution
There are $12$ beasts and $24$ birds.
Proof
Let $a$ and $b$ be the number of beasts and birds respectively.
If the anomalies had the usual number of legs, there would be $96$ feet altogether.
Hence we have:
\(\text {(1)}: \quad\) | \(\ds a + b\) | \(=\) | \(\ds 36\) | as they each have one head | ||||||||||
\(\text {(2)}: \quad\) | \(\ds 4 a + 2 b\) | \(=\) | \(\ds 96\) | as (normal) beasts have $4$ legs and birds $2$ | ||||||||||
\(\text {(3)}: \quad\) | \(\ds \leadsto \ \ \) | \(\ds 2 a + 2 b\) | \(=\) | \(\ds 72\) | $(1) \times 2$ | |||||||||
\(\ds \leadsto \ \ \) | \(\ds 2 a\) | \(=\) | \(\ds 24\) | $(2) - (3)$ | ||||||||||
\(\ds \leadsto \ \ \) | \(\ds a\) | \(=\) | \(\ds 12\) | |||||||||||
\(\ds \leadsto \ \ \) | \(\ds b\) | \(=\) | \(\ds 24\) |
$\blacksquare$
Sources
- 1932: Henry Ernest Dudeney: Puzzles and Curious Problems ... (previous) ... (next): Solutions: $148$. -- The Menagerie
- 1968: Henry Ernest Dudeney: 536 Puzzles & Curious Problems ... (previous) ... (next): Answers: $220$. The Menagerie