Henry Ernest Dudeney/Puzzles and Curious Problems/234 - Pile Driving/Solution

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Puzzles and Curious Problems by Henry Ernest Dudeney: $234$

Pile Driving
During some bridge-building operations a pile was being driven into the bed of the river.
A foreman remarked that at high water a quarter of the pile was embedded in the mud,
one-third was under water,
and $17$ feet $6$ inches above water.
What was the length of the pile?


Solution

$26$ feet $3$ inches.


Proof

Let $L$ feet be the length of the pile.


You may be tempted to do this:

\(\ds L\) \(=\) \(\ds \dfrac L 4 + \dfrac L 3 + 17 \tfrac 1 2\)
\(\ds \leadsto \ \ \) \(\ds 12 L\) \(=\) \(\ds 3 L + 4 L + 12 \times 17 \tfrac 1 2\)
\(\ds \leadsto \ \ \) \(\ds 5 L\) \(=\) \(\ds 210\)
\(\ds \leadsto \ \ \) \(\ds 5 L\) \(=\) \(\ds 42\)


No no no!

The part of the pile buried in the mud is also under water.

So:

\(\ds L\) \(=\) \(\ds \dfrac L 3 + 17 \tfrac 1 2\)
\(\ds \leadsto \ \ \) \(\ds 3 L\) \(=\) \(\ds L + 3 \times 17 \tfrac 1 2\)
\(\ds \leadsto \ \ \) \(\ds 2 L\) \(=\) \(\ds 52 \tfrac 1 2\)
\(\ds \leadsto \ \ \) \(\ds L\) \(=\) \(\ds 26 \tfrac 1 4\)

and it is seen that the proportion of the pile which is buried in mud is no more than a distraction.

$\blacksquare$


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