# Image of Union under Relation

## Theorem

Let $S$ and $T$ be sets.

Let $\RR \subseteq S \times T$ be a relation.

Let $S_1$ and $S_2$ be subsets of $S$.

Then:

$\RR \sqbrk {S_1 \cup S_2} = \RR \sqbrk {S_1} \cup \RR \sqbrk {S_2}$

That is, the image of the union of subsets of $S$ is equal to the union of their images.

### General Result

Let $S$ and $T$ be sets.

Let $\RR \subseteq S \times T$ be a relation.

Let $\powerset S$ be the power set of $S$.

Let $\mathbb S \subseteq \powerset S$.

Then:

$\ds \RR \sqbrk {\bigcup \mathbb S} = \bigcup_{X \mathop \in \mathbb S} \RR \sqbrk X$

### Family of Sets

Let $S$ and $T$ be sets.

Let $\family {S_i}_{i \mathop \in I}$ be a family of subsets of $S$.

Let $\RR \subseteq S \times T$ be a relation.

Then:

$\ds \RR \sqbrk {\bigcup_{i \mathop \in I} S_i} = \bigcup_{i \mathop \in I} \RR \sqbrk {S_i}$

where $\ds \bigcup_{i \mathop \in I} S_i$ denotes the union of $\family {S_i}_{i \mathop \in I}$.

## Proof

 $\ds t$ $\in$ $\ds \RR \sqbrk {S_1 \cup S_2}$ $\ds \leadstoandfrom \ \$ $\ds \exists s \in S_1 \cup S_2: \,$ $\ds t$ $\in$ $\ds \RR \sqbrk s$ Definition of Image of Subset under Relation $\ds \leadstoandfrom \ \$ $\ds \exists s: s \in S_1 \lor s \in S_2: \,$ $\ds t$ $\in$ $\ds \RR \sqbrk s$ Definition of Set Union $\ds \leadstoandfrom \ \$ $\ds t$ $\in$ $\ds \RR \sqbrk {S_1}$ Definition of Image of Subset under Relation $\, \ds \lor \,$ $\ds t$ $\in$ $\ds \RR \sqbrk {S_2}$ $\ds \leadstoandfrom \ \$ $\ds t$ $\in$ $\ds \RR \sqbrk {S_1} \cup \RR \sqbrk {S_2}$ Definition of Set Union

$\blacksquare$