Integral to Infinity of Sine p x over x/Proof 2

From ProofWiki
Jump to navigation Jump to search

Theorem

$\ds \int_0^\infty \frac {\sin p x} x \rd x = \begin {cases} \dfrac \pi 2 & : p > 0 \\ 0 & : p = 0 \\ -\dfrac \pi 2 & : p < 0 \end {cases}$


Proof