Minkowski Functional of Open Convex Set in Normed Vector Space is Sublinear Functional/Lemma
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Lemma
Let $\struct {X, \norm \cdot}$ be a normed vector space.
Let $C$ be an open convex subset of $X$ with $0 \in C$.
Then if:
- $\lambda \in \set {t > 0 : t^{-1} x \in C}$
we have:
- $\hointr \lambda \infty \subseteq \set {t > 0 : t^{-1} x \in C}$
Further:
- $\openint {\map {p_C} x} \infty \subseteq \set {t > 0 : t^{-1} x \in C}$
where $p_C$ is the Minkowski functional of $C$.
Proof
Let:
- $t \in \set {t > 0 : t^{-1} x \in C}$
Then:
- $t^{-1} x \in C$
Then from convexity, for all $\alpha \ge 1$ we have:
- $\alpha^{-1} t^{-1} x + \paren {1 - \alpha^{-1} } \times 0 \in C$
that is:
- $\alpha t \in \set {t > 0 : t^{-1} x \in C}$
so:
- $\hointr t \infty \subseteq \set {t > 0 : t^{-1} x \in C}$
Now let:
- $\lambda \in \openint {\map {p_C} x} \infty$
Then:
- $\map {p_C} x < \lambda$
From the definition of infimum, there exists:
- $\alpha \in \set {t > 0 : t^{-1} x \in C}$
such that:
- $\map {p_C} x < \alpha < \lambda$
Then, from the above computation we have:
- $\openint \alpha \infty \subseteq \set {t > 0 : t^{-1} x \in C}$
And, since $\alpha < \lambda$, we have:
- $\lambda \in \openint \alpha \infty$
so:
- $\lambda \in \set {t > 0 : t^{-1} x \in C}$
So, we obtain:
- $\openint {\map {p_C} x} \infty \subseteq \set {t > 0 : t^{-1} x \in C}$
$\blacksquare$