Modulo Polynomial Division/Examples/Arbitrary Example 1
Jump to navigation
Jump to search
Example of Modulo Polynomial Division
Let:
\(\ds \map f x\) | \(=\) | \(\ds x^3 - x^2 - 1\) | ||||||||||||
\(\ds \map g x\) | \(=\) | \(\ds x + 1\) |
Then $\map f x$ divided by $\map g x$ modulo $3$ is:
- $x^2 + x - 1$
Proof
\(\ds \paren {x + 1} \paren {x^2 + x - 1}\) | \(=\) | \(\ds x^3 + 2 x^2 - 1\) | ||||||||||||
\(\ds \) | \(\equiv\) | \(\ds x^3 - x^2 - 1\) | \(\ds \pmod 3\) |
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): division modulo $n$
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): division modulo $n$