Negative of Element in Field is Unique
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Theorem
Let $\struct {F, +, \times}$ be a field.
Let $a \in F$.
Then the negative $-a$ of $a$ is unique.
Proof 1
By definition, a field is a ring whose ring product less zero is an abelian group.
The result follows from Ring Negative is Unique.
$\blacksquare$
Proof 2
Let $b, c \in F$ such that both $a + b = 0$ and $a + c = 0$.
Thus:
\(\ds b + \paren {a + c}\) | \(=\) | \(\ds b + 0\) | as $c$ is a negative of $a$ | |||||||||||
\(\ds \) | \(=\) | \(\ds b\) | Definition of Field Zero |
But also:
\(\ds \paren {b + a} + c\) | \(=\) | \(\ds \paren {a + b} + c\) | Field Axiom $\text A1$: Associativity of Addition | |||||||||||
\(\ds \) | \(=\) | \(\ds 0 + c\) | as $b$ is a negative of $a$ | |||||||||||
\(\ds \) | \(=\) | \(\ds c\) | Definition of Field Zero |
So $b = c$ and the result follows.
$\blacksquare$