Polynomial Addition/Examples/Arbitrary Example 1
Jump to navigation
Jump to search
Example of Polynomial Addition
Let:
\(\ds P_1\) | \(=\) | \(\ds x^2 + 2 x + 3\) | ||||||||||||
\(\ds P_2\) | \(=\) | \(\ds 2 x^2 + x + 5\) |
Then:
- $P_1 + P_2 = 3 x^2 + 3 x + 8$
Proof
\(\ds P_1 + P_2\) | \(=\) | \(\ds \paren {x^2 + 2 x + 3} + \paren {2 x^2 + x + 5}\) | by hypothesis | |||||||||||
\(\ds \) | \(=\) | \(\ds \paren {x^2 + 2 x^2} + \paren {2 x + x} + \paren {3 + 5}\) | Definition of Polynomial Addition | |||||||||||
\(\ds \) | \(=\) | \(\ds 3 x^2 + 3 x + 8\) |
$\blacksquare$
Sources
- 1998: David Nelson: The Penguin Dictionary of Mathematics (2nd ed.) ... (previous) ... (next): addition
- 2008: David Nelson: The Penguin Dictionary of Mathematics (4th ed.) ... (previous) ... (next): addition