Sum of Equal and Opposite Harmonic Waves form Stationary Wave
Jump to navigation
Jump to search
Theorem
Let $\phi_1$ be a harmonic wave which is propagated along the $x$-axis in the positive direction with constant velocity $c$.
Let $\phi_2$ be a harmonic wave travelling with constant velocity $-c$, that is, at the same speed as $\phi_1$ but in the opposite direction.
Then their sum $\phi_1 + \phi_2$ describes a stationary wave.
Proof
From Equation of Harmonic Wave: Wave Number and Frequency:
- $(1): \quad \map {\phi_1} {x, t} = a \map \cos {2 \pi \paren {k x - \nu t} }$
where:
- $k$ denotes the wave number of $\phi_1$
- $\nu$ denotes the frequency of $\phi_1$.
From Equation of Wave with Constant Velocity: Corollary, the equation of $\phi_2$ is:
- $(2): \quad \map {\phi_2} {x, t} = a \map \cos {2 \pi \paren {k x + \nu t} }$
Then we have:
\(\ds \map {\phi_1} {x, t} + \map {\phi_2} {x, t}\) | \(=\) | \(\ds a \map \cos {2 \pi \paren {k x - \nu t} } + a \map \cos {2 \pi \paren {k x + \nu t} }\) | from $(1)$ and $(2)$ | |||||||||||
\(\ds \) | \(=\) | \(\ds 2 a \map \cos {\dfrac {2 \pi \paren {k x - \nu t} + 2 \pi \paren {k x + \nu t} } 2} \map \cos {\dfrac {2 \pi \paren {k x - \nu t} - 2 \pi \paren {k x + \nu t} } 2}\) | Cosine plus Cosine | |||||||||||
\(\ds \) | \(=\) | \(\ds 2 a \map \cos {2 \pi k x} \map \cos {2 \pi \paren {-\nu t} }\) | simplification | |||||||||||
\(\ds \) | \(=\) | \(\ds 2 a \map \cos {2 \pi k x} \map \cos {2 \pi \nu t}\) | Cosine Function is Even |
This needs considerable tedious hard slog to complete it. In particular: It remains to be shown that this is the equation of a stationary wave. To discuss this page in more detail, feel free to use the talk page. When this work has been completed, you may remove this instance of {{Finish}} from the code.If you would welcome a second opinion as to whether your work is correct, add a call to {{Proofread}} the page. |
Sources
- 1955: C.A. Coulson: Waves (7th ed.) ... (previous) ... (next): Chapter $\text {I}$: The Equation of Wave Motion: $\S 6$: $(15)$