Talk:Characteristic Function of Union

From ProofWiki
Jump to navigation Jump to search
$(1):\quad \chi_{A \cup B} = \chi_A \chi_B$

... really?

$(1):\quad \chi_{A \cup B} = 1 - (1 - \chi_A) (1 - \chi_B)$

more like? --prime mover 19:11, 12 March 2012 (EDT)

Not what Schilling gives, but thanks anyway for noticing; corrected. --Lord_Farin 19:13, 12 March 2012 (EDT)