Biconditional is Transitive
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Theorem
The biconditional operator is transitive:
Formulation 1
- $p \iff q, q \iff r \vdash p \iff r$
Formulation 2
- $\vdash \paren {\paren {p \iff q} \land \paren {q \iff r} } \implies \paren {p \iff r}$