Chu-Vandermonde Identity/Examples/2 from e + pi/Proof 1
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Example of Use of Chu-Vandermonde Identity
Let $r = e$, $s = \pi$ and $n = 2$
- $\ds \binom {e + \pi} 2 = \sum_{k \mathop = 0}^2 \binom e k \binom \pi {2 - k}$
Proof
From the Chu-Vandermonde Identity:
- $\ds \sum_{k \mathop = 0}^n \binom r k \binom s {n - k} = \binom {r + s} n$
The result follows on setting $r = e$, $s = \pi$ and $n = 2$.
$\blacksquare$