Condition for Lipschitz Condition to be Satisfied
From ProofWiki
Theorem
Let $f$ be a real function.
Then $f$ satisfies the Lipschitz condition on a closed real interval $\left[{a .. b}\right]$ if:
- $\forall y \in \left[{a .. b}\right]: \exists A \in \R: \left|{\phi^{\prime} \left({y}\right)}\right| \le A$
Proof
Integrating both sides of $\left|{\phi^{\prime} \left({y}\right)}\right| \le A$ gives us:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\) | \(\displaystyle \left\vert{\phi^{\prime} \left({y}\right)}\right\vert \le A\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle -A \le \phi^{\prime} \left({y}\right) \le A\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle \int {-A} \ \mathrm dy \le \phi \left({y}\right) \le \int A \ \mathrm dy\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle -A y \le \phi \left({y}\right) \le A y\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\implies\) | \(\displaystyle \left\vert{\phi \left({y}\right)}\right\vert \le A y\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
On the interval $\left[{a .. b}\right]$ it follows that $\left|{\phi \left({y}\right)}\right|$ is bounded by the greater of $A a$ and $A b$.
Hence the result.
$\blacksquare$