Definition:Convergent Sequence

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Definition

Topological Space

Let $T = \left({A, \vartheta}\right)$ be a topological space.

Let $\left \langle {x_k} \right \rangle$ be a sequence in $T$.


Then $\left \langle {x_k} \right \rangle$ converges to the limit $\alpha \in T$ if:

for any open set $U \in \vartheta$ such that $\alpha \in U$: $\exists N \in \R: n > N \implies x_n \in U$


This can be alternatively stated:

$\left \langle {x_k} \right \rangle$ converges to the limit $\alpha \in T$ if:

every open set in $T$ containing $\alpha$ contains all but a finite number of terms of $\left \langle {x_n} \right \rangle$.


Such a sequence is convergent.


Metric Space

Let $\left({X, d}\right)$ be a metric space.

Let $\left \langle {x_k} \right \rangle$ be a sequence in $X$.


Then $\left \langle {x_k} \right \rangle$ converges to the limit $l$ iff:

$\forall \epsilon > 0: \exists N \in \R: n > N \implies d \left({x_n, l}\right) < \epsilon$

Or equivalently, using the definition of neighborhood:

$\forall \epsilon > 0: \exists N \in \R: n > N \implies x_n \in N_\epsilon \left({l}\right)$


We can write:

$x_n \to l$ as $n \to \infty$

or:

$\displaystyle \lim_{n \to \infty} x_n \to l$

This is voiced:

As $n$ tends to infinity, $x_n$ tends to (the limit) $l$.


It can be seen that by the definition of open set in a metric space, this definition is equivalent to that for convergence in a topological space.


Comment

The sequence $x_1, x_2, x_3, \ldots, x_n, \ldots$ can be thought of as a set of approximations to $l$, in which the higher the $n$ the better the approximation.

The distance $\left|{x_n - l}\right|$ between $x_n$ and $l$ can then be thought of as the error arising from approximating $l$ by $x_n$.


Note the way the definition is constructed.

Given any value of $\epsilon$, however small, we can always find a value of $N$ such that ...

If you pick a smaller value of $\epsilon$, then (in general) you would have to pick a larger value of $N$ - but the implication is that, if the sequence is convergent, you will always be able to do this.


Note also that $N$ depends on $\epsilon$. That is, for each value of $\epsilon$ we (probably) need to use a different value of $N$.


Standard Number Fields

When $X$ is one of the standard number fields $\Q, \R, \C$, and the metric $d$ is the usual (Euclidean) metric, the condition on convergence becomes:


$\left \langle {x_k} \right \rangle$ converges to the limit $l$ iff:

$\forall \epsilon > 0: \exists N \in X: n > N \implies \left|{x_n - l}\right| < \epsilon$

where $\left|{x}\right|$ is the modulus of $x$.


The validity of this definition derives from the fact that:


Divergent Sequence

A sequence which is not convergent is divergent.

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