Definition:Lipschitz Equivalence

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Metric Spaces

Let $M = \left({A, d}\right)$ and $M^{\prime} = \left({A^{\prime}, d^{\prime}}\right)$ be metric spaces.

Let $f: M \to M^{\prime}$ be a mapping such that $\exists h, k \in \R: h > 0, k > 0$ such that:

$\forall x, y \in A: h d^{\prime}\left({f \left({x}\right), f \left({y}\right)}\right) \le d \left({x, y}\right) \le k d^{\prime}\left({f \left({x}\right), f \left({y}\right)}\right)$


Then $f$ is a Lipschitz equivalence, and $M$ and $M^{\prime}$ are described as Lipschitz equivalent.


Metrics

Let $A$ be a set upon which there are two metrics imposed: $d$ and $d^{\prime}$.

Let $\exists h, k \in \R: h > 0, k > 0$ such that:

$\forall x, y \in A: h d^{\prime}\left({x, y}\right) \le d \left({x, y}\right) \le k d^{\prime}\left({x, y}\right)$


Then $d$ and $d^{\prime}$ are described as Lipschitz equivalent.


This is clearly an equivalence relation.


Source of Name

This entry was named for Rudolf Lipschitz.


Sources

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