Definition:Maximal
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Definition
Ordered Set
Let $\left({S, \preceq}\right)$ be a poset.
Let $T \subseteq S$ be a subset of $S$.
An element $x \in T$ is a maximal element of $T$ iff:
- $x \preceq y \implies x = y$
That is, the only element of $S$ that $x$ precedes or is equal to is itself.
Alternatively, this can be put as:
$x \in T$ is a maximal element of $T$ iff:
- $\neg \exists y \in T: x \prec y$
where $x \prec y$ denotes that $x \preceq y \land x \ne y$.
Maximal Set
Let $S$ be a set.
Let $\mathcal P \left({S}\right)$ be the power set of $S$.
Let $\mathcal T \subseteq \mathcal P \left({S}\right)$ be a subset of $\mathcal P \left({S}\right)$.
Let $\left({\mathcal T, \subseteq}\right)$ be the poset formed on $\mathcal T$ by $\subseteq$ considered as an ordering.
Then $T \in \mathcal T$ is a maximal set of $\mathcal T$ iff $T$ is a maximal element of $\left({\mathcal T, \subseteq}\right)$.
That is:
- $\forall X \in \mathcal T: T \subseteq X \implies T = X$
Mapping
Let $f$ be a mapping defined on a subset of the real numbers $S \subseteq \R$.
Let $f$ be bounded above by a supremum $B$.
It may or may not be the case that $\exists x \in S: f \left({x}\right) = B$.
If such a value exists, it is called the maximal value or maximum of $f$ on $S$, and that this maximum is attained at $x$.