Definition:Order Isomorphism

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This page is about isomorphisms in order theory. For other uses, see Definition:Isomorphism.


Contents

Definition

Let $\left({S, \preceq_1}\right)$ and $\left({T, \preceq_2}\right)$ be posets.

Let $\phi: S \to T$ be a bijection such that:

Then $\phi$ is an order isomorphism.


That is, $\phi$ is an order isomorphism iff:

$\forall x, y \in S: x \, \preceq_1 \, y \iff \phi \left({x}\right) \, \preceq_2 \, \phi \left({y}\right)$


So an order isomorphism can be described as a bijection that preserves ordering in both directions.


Two posets are (order) isomorphic if there exists such an order isomorphism between them.


Warning

It does not necessarily follow that if:

$\phi: S \to T$ is a bijection which is order-preserving

then:

$\phi^{-1}: T \to S$ is order-preserving.


Example

Let $S = \mathcal P \left({\left\{{a, b}\right\}}\right), T = \left\{{1, 2, 3, 4}\right\}$.

From Subset Relation on Power Set is Partial Ordering, we have that $\left({S, \subseteq}\right)$ is a poset.

Clearly so is $\left({T, \le}\right)$ (although its ordering is in fact total, it is still technically a poset).

Let $\phi: S \to T$ be defined as:

  • $\phi \left({\varnothing}\right) = 1$
  • $\phi \left({\left\{{a}\right\}}\right) = 2$
  • $\phi \left({\left\{{b}\right\}}\right) = 3$
  • $\phi \left({\left\{{a, b}\right\}}\right) = 4$

It is easily verified that $\phi: \left({S, \subseteq}\right) \to \left({T, \le}\right)$ is a bijection which is order-preserving.

But note that while $2 \le 3$, it is not the case that $\left\{{a}\right\} \subseteq \left\{{b}\right\}$ and so $\phi^{-1}$ is not order-preserving.


Also see

  • Results about order isomorphisms can be found here.


Sources

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