Divisor Sum of 616
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Example of Divisor Sum of Integer
- $\map {\sigma_1} {616} = 1440$
where $\sigma_1$ denotes the divisor sum function.
Proof
From Divisor Sum of Integer:
- $\ds \map {\sigma_1} n = \prod_{1 \mathop \le i \mathop \le r} \frac {p_i^{k_i + 1} - 1} {p_i - 1}$
where $n = \ds \prod_{1 \mathop \le i \mathop \le r} p_i^{k_i}$ denotes the prime decomposition of $n$.
We have that:
- $616 = 2^3 \times 7 \times 11$
Hence:
\(\ds \map {\sigma_1} {616}\) | \(=\) | \(\ds \frac {2^4 - 1} {2 - 1} \times \paren {7 + 1} \times \paren {11 + 1}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 15 \times 8 \times 12\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds \paren {3 \times 5} \times 2^3 \times \paren {2^2 \times 3}\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 2^5 \times 3^2 \times 5\) | ||||||||||||
\(\ds \) | \(=\) | \(\ds 1440\) |
$\blacksquare$