Elementary Properties of Event Space

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Theorem

Let $\mathcal E$ be an experiment with a probability space $\left({\Omega, \Sigma, \Pr}\right)$.


The event space $\Sigma$ of $\mathcal E$ has the following properties:

$(1) \quad \varnothing \in \Sigma$
$(2) \quad \Omega \in \Sigma$
$(3) \quad A, B \in \Sigma \implies A \cap B \in \Sigma$
$(4) \quad A, B \in \Sigma \implies A \setminus B \in \Sigma$
$(5) \quad A, B \in \Sigma \implies A \ast B \in \Sigma$
$(6) \quad A_1, A_2, \ldots \in \Sigma \implies \displaystyle \bigcap_{i=1}^\infty A_i \in \Sigma$, that is, the intersection of any countable collection of elements of $\Sigma$ is also in $\Sigma$.


In the above:


Proof

By definition, a probability space $\left({\Omega, \Sigma, \Pr}\right)$ is a measure space.

So, again by definition, an event space $\Sigma$ is a sigma-algebra on $\Omega$. Thus the requirements above.


As $\Sigma$ is a sigma-algebra, it is also by definition an algebra of sets.

It follows from Properties of Algebras of Sets and Equivalence of Definitions of Algebra of Sets, that:

  • $\varnothing \in \Sigma$
  • $\Omega \in \Sigma$
  • $A, B \in \Sigma \implies A \cap B \in \Sigma$
  • $A, B \in \Sigma \implies A \setminus B \in \Sigma$
  • $A, B \in \Sigma \implies A \ast B \in \Sigma$.
$\displaystyle A_1, A_2, \ldots \in \Sigma \implies \bigcap_{i=1}^\infty A_i \in \Sigma$

by definition of delta-algebra.

$\blacksquare$


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