Equation of Hyperbola in Reduced Form/Cartesian Frame/Parametric Form 2

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Theorem

Let $K$ be a hyperbola such that:

the transverse axis of $K$ has length $2 a$
the conjugate axis of $K$ has length $2 b$.


Let $K$ be aligned in a cartesian plane in reduced form.


$K$ can be expressed in parametric form as:

$\begin {cases} x = a \sec \theta \\ y = b \tan \theta \end {cases}$


Proof

Let the point $\tuple {x, y}$ satisfy the equations:

\(\ds x\) \(=\) \(\ds a \sec \theta\)
\(\ds y\) \(=\) \(\ds b \tan \theta\)


Then:

\(\ds \frac {x^2} {a^2} - \frac {y^2} {b^2}\) \(=\) \(\ds \frac {\paren {a \sec \theta}^2} {a^2} - \frac {\paren {b \tan \theta}^2} {b^2}\)
\(\ds \) \(=\) \(\ds \frac {a^2} {a^2} \sec^2 \theta - \frac {b^2} {b^2} \tan^2 \theta\)
\(\ds \) \(=\) \(\ds \sec^2 \theta - \tan^2 \theta\)
\(\ds \) \(=\) \(\ds 1\) Difference of Squares of Secant and Tangent

$\blacksquare$


Sources