Field of Integers Modulo Prime is Prime Field
From ProofWiki
Theorem
Let $p$ be a prime number.
Let $\left({\Z_p, +, \times}\right)$ be the field of integers modulo $p$.
Then $\left({\Z_p, +, \times}\right)$ is a prime field.
Proof
If $\left({F, +, \times}\right)$ is a subfield of $\left({\Z_p, +, \times}\right)$, then $\left({F, +}\right)$ is a subgroup of $\left({\Z_p, +}\right)$.
But from Prime Group has No Proper Subgroups, $\left({\Z_p, +}\right)$ has no proper subgroup except the Trivial Group.
Hence $F = \Z_p$ and so follows the result.
$\blacksquare$
Sources
- Iain T. Adamson: Introduction to Field Theory (1964)... (previous)... (next): $\S 1.2$: Example $2$