Homomorphism from Reals to Circle Group
From ProofWiki
Theorem
Let $\left({\R, +}\right)$ be the Additive Group of Real Numbers.
Let $\left({K, \times}\right)$ be the circle group.
Let $\phi: \left({\R, +}\right) \to \left({K, \times}\right)$ be the mapping defined as $\phi \left ({x}\right) = e^{i x}$.
Then $\phi$ is a (group) homomorphism.
Proof
Let $x, y \in \R$. Then:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \phi \left ({x}\right) \times \phi \left ({y}\right)\) | \(=\) | \(\displaystyle e^{i x} e^{i y}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle e^{i \left({x + y}\right)}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \phi \left({x + y}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
$\blacksquare$