Homomorphism from Reals to Circle Group

From ProofWiki
Jump to: navigation, search

Theorem

Let $\left({\R, +}\right)$ be the Additive Group of Real Numbers.

Let $\left({K, \times}\right)$ be the circle group.

Let $\phi: \left({\R, +}\right) \to \left({K, \times}\right)$ be the mapping defined as $\phi \left ({x}\right) = e^{i x}$.


Then $\phi$ is a (group) homomorphism.


Proof

Let $x, y \in \R$. Then:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \phi \left ({x}\right) \times \phi \left ({y}\right)\) \(=\) \(\displaystyle e^{i x} e^{i y}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle e^{i \left({x + y}\right)}\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(=\) \(\displaystyle \phi \left({x + y}\right)\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    

$\blacksquare$

Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense