Integrally Closed is Local Property
From ProofWiki
Theorem
Let $A$ be an integral domain.
For a prime ideal $\mathfrak p$ of $A$, let $A_{\mathfrak p}$ denote the localisation at $S = A \backslash \mathfrak p$.
Then the following are equivalent:
- 1. $A$ is integrally closed
- 2. $A_{\mathfrak p}$ is integrally closed for all prime ideals $\mathfrak p$.
- 3.$A_{\mathfrak m}$ is integrally closed for all maximal ideals $\mathfrak m$.
Proof
1. $\Rightarrow$ 2.
Let $Q(R)$ denote the quotient field of a domain $R$.
Since $Q(A_{\mathfrak p}) = Q(A)$, by Localisation Preserves Integral Closure, we have that $A_{\mathfrak p}$ is integrally closed for all prime ideals $\mathfrak p$.
2. $\Rightarrow$ 3.
This is true because a Maximal Ideal is Prime.
3. $\Rightarrow$ 1.