Interior of Finite Intersection equals Intersection of Interiors
From ProofWiki
Theorem
Let $T$ be a topological space.
Let $n \in \N$.
Let $\forall i \in \left[{1 . . n}\right]: H_i \subseteq T$.
Then:
- $\displaystyle \left({\bigcap_{i=1}^n H_i}\right)^\circ = \bigcap_{i=1}^n H_i^\circ$
where $H_i^\circ$ denotes the interior of $H_i$.
Proof
In the following, $H_i^-$ denotes the closure of the set $H_i$.
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \left({\bigcap_{i=1}^n H_i}\right)^\circ\) | \(=\) | \(\displaystyle T \setminus \left({T \setminus \bigcap_{i=1}^n H_i}\right)^-\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Complement of Interior equals Closure of Complement | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle T \setminus \left({\left({\bigcup_{i=1}^n \left({T \setminus H_i}\right)}\right)^-}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | De Morgan's Laws | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle T \setminus \left({\bigcup_{i=1}^n \left({T \setminus H_i}\right)^-}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Closure of Finite Union Equals Union of Closures | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle T \setminus \left({\bigcup_{i=1}^n T \setminus H_i^\circ}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Complement of Interior equals Closure of Complement | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle T \setminus \left({T \setminus \left({\bigcap_{i=1}^n H_i^\circ}\right)}\right)\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | De Morgan's Laws | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \bigcap_{i=1}^n H_i^\circ\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Relative Complement of Relative Complement |
$\blacksquare$
Sources
- Lynn Arthur Steen and J. Arthur Seebach, Jr.: Counterexamples in Topology (1970)... (previous)... (next): $\text{I}: \ \S 1$: Closures and Interiors