Interval Defined by Absolute Value

From ProofWiki
Jump to: navigation, search

Theorem

Let $\xi, \delta \in \R$ be real numbers.

Let $\delta > 0$.


Then:

$\left\{{x \in \R: \left\vert{\xi - x}\right\vert < \delta}\right\} = \left({\xi - \delta .. \xi + \delta}\right)$

where $\left({\xi - \delta .. \xi + \delta}\right)$ is the open real interval between $\xi - \delta$ and $\xi + \delta$.


Similarly:

$\left\{{x \in \R: \left\vert{\xi - x}\right\vert \le \delta}\right\} = \left[{\xi - \delta .. \xi + \delta}\right]$

where $\left[{\xi - \delta .. \xi + \delta}\right]$ is the closed real interval between $\xi - \delta$ and $\xi + \delta$.


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \left\vert{\xi - x}\right\vert\) \(<\) \(\displaystyle \delta\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle -\delta\) \(<\) \(\displaystyle \xi - x < \delta\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Corollary to negative of absolute value          
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \delta\) \(>\) \(\displaystyle x - \xi - x > -\delta\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \iff\) \(\displaystyle \) \(\displaystyle \xi + \delta\) \(>\) \(\displaystyle x > \xi - \delta\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    


But:

$\left({\xi - \delta .. \xi + \delta}\right) = \left\{{x \in \R: \xi - \delta < x < \xi + \delta}\right\}$


The other result follows similarly.

$\blacksquare$


Sources

Personal tools
Namespaces
Variants
Actions
Navigation
ProofWiki.org
ToDo
Toolbox
Google AdSense