Interval Defined by Absolute Value
From ProofWiki
Theorem
Let $\xi, \delta \in \R$ be real numbers.
Let $\delta > 0$.
Then:
- $\left\{{x \in \R: \left\vert{\xi - x}\right\vert < \delta}\right\} = \left({\xi - \delta .. \xi + \delta}\right)$
where $\left({\xi - \delta .. \xi + \delta}\right)$ is the open real interval between $\xi - \delta$ and $\xi + \delta$.
Similarly:
- $\left\{{x \in \R: \left\vert{\xi - x}\right\vert \le \delta}\right\} = \left[{\xi - \delta .. \xi + \delta}\right]$
where $\left[{\xi - \delta .. \xi + \delta}\right]$ is the closed real interval between $\xi - \delta$ and $\xi + \delta$.
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \left\vert{\xi - x}\right\vert\) | \(<\) | \(\displaystyle \delta\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle -\delta\) | \(<\) | \(\displaystyle \xi - x < \delta\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Corollary to negative of absolute value | ||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle \delta\) | \(>\) | \(\displaystyle x - \xi - x > -\delta\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \iff\) | \(\displaystyle \) | \(\displaystyle \xi + \delta\) | \(>\) | \(\displaystyle x > \xi - \delta\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
But:
- $\left({\xi - \delta .. \xi + \delta}\right) = \left\{{x \in \R: \xi - \delta < x < \xi + \delta}\right\}$
The other result follows similarly.
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 2.10 \ (2)$