Powers of Group Elements/Product of Indices
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Theorem
Let $\left({G,*}\right)$ be a group whose identity is $e$.
Let $g \in G$.
Then:
- $\forall m, n \in \Z: \left({g^m}\right)^n = g^{m n} = \left({g^n}\right)^m$
Additive Notation
This can also be written in additive notation as:
- $\forall m, n \in \Z: n \left({m g}\right) = \left({m n}\right) g = m \left({n g}\right)$
Proof
All elements of a group are invertible, so we can directly use the result from Index Laws for Monoids: Product of Indices:
- $\forall m, n \in \Z: g^{m n} = \left({g^m}\right)^n = \left({g^n}\right)^m$
$\blacksquare$
Sources
- J.A. Green: Sets and Groups (1965)... (previous)... (next): $\S 4.6$: Example $87 \ \text{(vii)}$
- Thomas A. Whitelaw: An Introduction to Abstract Algebra (1978)... (previous)... (next): $\S 35.10$
- John F. Humphreys: A Course in Group Theory (1996): $\S 3$: Proposition $3.8$