Quotient Theorem for Surjections
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Theorem
For any surjection $f: S \to T$, there is one and only one bijection $r: S / \mathcal R_f \to T$ such that:
- $r \circ q_{\mathcal R_f} = f$
where:
- $\mathcal R_f$ is the equivalence induced by $f$;
- $r: S / \mathcal R_f \to T$ is the renaming mapping;
- $q_{\mathcal R_f}: S \to S / \mathcal R_f$ is the quotient mapping induced by $\mathcal R_f$.
Also known as the factor theorem for surjections.
Proof
From the definition of Induced Equivalence, the mapping $f: S \to T$ induces an equivalence $\mathcal R_f$ on its domain.
As $f: S \to T$ is a surjection, $T = \operatorname{Im} \left({f}\right)$ from Surjection iff Image equals Codomain.
From Renaming Mapping is a Bijection, the renaming mapping $r: S / \mathcal R_f \to T$ is a bijection, where $S / \mathcal R_f$ is the quotient set of $S$ by $\mathcal R_f$.
Clearly:
- $r \circ q_{\mathcal R_f} = f$.
- $r$ is the only mapping $r: S / \mathcal R_f \to T$ that satisfies this equality.
$\blacksquare$
Also see
Sources
- Seth Warner: Modern Algebra (1965)... (previous)... (next): $\S 10$: Theorem $10.5$