Real Addition is Commutative
From ProofWiki
Theorem
The operation of addition on the set of real numbers $\R$ is commutative:
- $\forall x, y \in \R: x + y = y + x$
Proof
From the definition, the real numbers are the set of all equivalence classes $\left[\!\left[{\left \langle {x_n} \right \rangle}\right]\!\right]$ of Cauchy sequences of rational numbers.
Let $x = \left[\!\left[{\left \langle {x_n} \right \rangle}\right]\!\right], y = \left[\!\left[{\left \langle {y_n} \right \rangle}\right]\!\right]$, where $\left[\!\left[{\left \langle {x_n} \right \rangle}\right]\!\right]$ and $\left[\!\left[{\left \langle {y_n} \right \rangle}\right]\!\right]$ are such equivalence classes.
Thus:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle x + y\) | \(=\) | \(\displaystyle \left[\!\left[{\left \langle {x_n} \right \rangle}\right]\!\right] + \left[\!\left[{\left \langle {y_n} \right \rangle}\right]\!\right]\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | by definition of real numbers | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \left[\!\left[{\left \langle {x_n + y_n} \right \rangle}\right]\!\right]\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | by definition of real addition | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \left[\!\left[{\left \langle {y_n + x_n} \right \rangle}\right]\!\right]\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Rational Addition is Commutative | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \left[\!\left[{\left \langle {y_n} \right \rangle}\right]\!\right] + \left[\!\left[{\left \langle {x_n} \right \rangle}\right]\!\right]\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | by definition of real addition | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle y + x\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) |
$\blacksquare$
Sources
- Iain T. Adamson: Introduction to Field Theory (1964)... (previous)... (next): $\S 1.1$