Real Number Inequalities can be Added

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Theorem

Let $a, b, c, d \in \R$ such that $a > b$ and $c > d$.


Then $a + c > b + d$.


Proof

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle a\) \(>\) \(\displaystyle b\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle a + c\) \(>\) \(\displaystyle b + c\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Real Number Ordering is Compatible with Addition          


\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle c\) \(>\) \(\displaystyle d\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle b + c\) \(>\) \(\displaystyle b + d\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Real Number Ordering is Compatible with Addition          


Finally:

\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle a + c\) \(>\) \(\displaystyle b + c\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \) \(\displaystyle \) \(\displaystyle b + c\) \(>\) \(\displaystyle b + d\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)                    
\(\displaystyle \) \(\displaystyle \implies\) \(\displaystyle \) \(\displaystyle a + c\) \(>\) \(\displaystyle b + d\) \(\displaystyle \) \(\displaystyle \) \(\displaystyle \)          Trichotomy Law for Real Numbers          

$\blacksquare$


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