Real Number Inequalities can be Added
From ProofWiki
Theorem
Let $a, b, c, d \in \R$ such that $a > b$ and $c > d$.
Then $a + c > b + d$.
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle a\) | \(>\) | \(\displaystyle b\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle a + c\) | \(>\) | \(\displaystyle b + c\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Real Number Ordering is Compatible with Addition |
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle c\) | \(>\) | \(\displaystyle d\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle b + c\) | \(>\) | \(\displaystyle b + d\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Real Number Ordering is Compatible with Addition |
Finally:
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle a + c\) | \(>\) | \(\displaystyle b + c\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle b + c\) | \(>\) | \(\displaystyle b + d\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \implies\) | \(\displaystyle \) | \(\displaystyle a + c\) | \(>\) | \(\displaystyle b + d\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Trichotomy Law for Real Numbers |
$\blacksquare$
Sources
- K.G. Binmore: Mathematical Analysis: A Straightforward Approach (1977)... (previous)... (next): $\S 1.8 \ (3)$