Reciprocal of One Plus Cosecant
From ProofWiki
Theorem
- $\displaystyle \frac {\cos^2 x + 3 \sin x - 1} {\cos^2 x + 2 \sin x + 2} = \frac 1 {1 + \csc x}$
Proof
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \frac {\cos^2 x + 3 \sin x - 1} {\cos^2 x + 2 \sin x + 2}\) | \(=\) | \(\displaystyle \frac {1 - \sin^2 x + 3 \sin x - 1} {1 - \sin^2 x + 2 \sin x + 2}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | Sum of Squares of Sine and Cosine | ||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \frac {\sin^2 x - 3 \sin x} {\sin^2 x - 2 \sin x - 3}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \frac{\sin x \left({\sin x - 3}\right)} {\left({\sin x - 3}\right) \left({\sin x + 1}\right)}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \frac {\sin x} {\sin x + 1}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \frac 1 {1 + \dfrac 1 {\sin x} }\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | |||
| \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | \(=\) | \(\displaystyle \frac 1 {1 + \csc x}\) | \(\displaystyle \) | \(\displaystyle \) | \(\displaystyle \) | by definition of cosecant |
$\blacksquare$